Beingcert Certified Python Programmer Exam
Last Update 4 days ago
Total Questions : 0
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What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main () {
int t[] = {1,2,3,4,5,1,2,3,5,4};
vector
vector
int m1[] = {1, 3, 2};
it = find_end (v.begin(), v.end(), m1, m1+3);
if (it != v.end())
cout << "Found at position: " << it?v.begin() << endl;
return 0;
}
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: true false
#include
#include
using namespace std;
int main ()
{
bool a,b;
cin>>boolalpha>>a>>b;
cout< return 0; } Program will output:
What happens when you attempt to compile and run the following code?
#include
#include
int main ()
{
int t[]={1,2,3,4,5};
std::vector
std::vector
v1.resize(10);
v2.reserve(10);
std::vector
while (i != v1.end()) { std::cout< i = v2.begin();ii=0; while (i != v2.end()) { std::cout< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main ()
{
int t[] = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 };
vector
deque
deque
d2 = d1;
d2.insert(d1.rbegin(), 10);
for(int i = 0; i { cout< } return 0; }
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: 64 100
#include
#include
#include
#include
using namespace std;
int main ()
{
string s;
getline(cin, s);
stringstream input(s);
stringstream output;
for( ; !input.fail() ; )
{
int i;
input>>hex>>i;
output< } cout< return 0; } What will be the result assuming that user will enter following sequence: 64 100:
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
template
class A {
T_v;
public:
A() {}
A(T v): _v(v){}
T getV() { return _v; }
void add(T & a) { _v+=a; }
void add(string & a) {
_v.insert(0, a);
}
};
int main()
{
A
string s(" world!");
a.add(s);
cout << a.getV() < return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; deque d1(t, t+10); sort(d1.begin(), d1.end()); deque::iterator it = upper_bound(d1.begin(), d1.end(), B(4), greater()); for_each(it, d1.end(), Out(cout)); cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
int main()
{
int t[] ={ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
deque
queue
queue
queue
queue
mylist.clear();third.clear();
cout< cout< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t1[]={3,2,4,1,5}; int t2[]={5,6,8,2,1}; vector sort(t1, t1+5); sort(t2, t2+5); set_union(t1,t1+5,t2,t2+5,v1.begin()); for_each(v1.begin(), v1.end(), Out return 0; } Program outputs:
What will happen when you attempt to compile and run the code below, assuming that file test.in contains the following sequence: 1 2 3?
#include
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out< int main () { ifstream f("test.in"); list for( ; f.good() ; ) { int i; f>>i; l.push_back(i); } f.close(); for_each(l.begin(), l.end(), Out return 0; } Program will output:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class A {
int a;
public:
A(int a) : a(a) {}
int getA() const { return a; } void setA(int a) { this?>a = a; }
};
int main () {
int t[] = {1,2,3,2,3,5,1,2,7,3,2,1,10, 4,4,5};
deque
int number = count(d.begin(), d.end(), 2);
cout<< number< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
int main() {
int t[] = { 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };
string s[] = { "one", "one", "two", "two", "three","three", "four", "four", "five", "five"};
map
for (int i = 0; i < 10; i++) {
m.push_back(pair
}
for (map
cout << i?>first << " ";
}
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { B t1[]={3,2,4,1,5}; B t2[]={6,10,8,7,9}; vector v1(10); sort(t1, t1+5); sort(t2, t2+5); merge(t1,t1+5,t2,t2+5,v1.begin()); for_each(v1.begin(), v1.end(), Out(cout));cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int() const { return val; };};
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out< int main () { int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; fstream f("test.out", ios::trunc|ios::out); list l(t, t+10); for_each(l.begin(), l.end(), Out(f)); f.close(); f.open("test.out"); for( ; f.good() ; ) { B i; f>>i; cout< } f.close(); return 0; }
Which stack initialization (line numbers) are correct? Choose all that apply.
#include
#include
#include
#include
#include
using namespace std;
int main()
{
deque
list
vector
stack
stack
stack
stack
stack
return 0;
}
Which method added to class B at the marked spot will allow the code below to compile? Choose all possible solutions.
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;}
/* Insert Code Here */
};
ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; vector v1(t, t+10); sort(v1.begin(), v1.end(), greater()); for_each(v1.begin(), v1.end(), Out(cout));cout< return 0; }
What happens when you attempt to compile and run the following code? Choose all that apply.
#include
#include
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out< int main () { int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; fstream f("test.out", ios::trunc|ios::out); list for_each(l.begin(), l.end(), Out f.close(); f.open("test.out"); for( ; f.good() ; ) { int i; f>>i; cout< } f.close(); return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
set
vector
swap(s1, v1);
for_each(v1.begin(), v1.end(), myfunction);
for_each(s1.begin(), s1.end(), myfunction);
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
int main()
{
deque
queue
queue
fourth.push(10);fourth.push(11);fourth.push(12);
queue
fifth.push(10);fifth.push(11);fifth.push(12); // Line I
while(!fifth.empty())
{
cout< fifth.pop(); // Line III } while (!fourth.empty()) { cout << fourth.front() << " "; fourth.pop(); // Line IV } return 0; }
What happens when you attempt to compile and run the following code? Choose all that apply.
#include
#include
using namespace std;
int main ()
{
vector
v1.push_back(3);
cout< return 0; }
What will happen when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
while (start != end) {
std::cout << *start << " "; start++;
}
}
int main(){
vector
set
for(int i=10; i>0; i??) {
v.push_back(i);
s.push_back(i);
}
print(v.begin(), v.end()); print(s.begin(), s.end());cout< return 0; } The output will be:
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: 1 2 3 4 quit
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out< int main () { list while(cin.good()) { string s; cin>>s; if (s == "quit") break; l.push_back(s); } for_each(l.begin(), l.end(), Out return 0; } Program will output:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int main() {
vector
fill(v1.begin()+2, v1.end()?2,2);
fill_n(v1.begin()+4,2,3);
for_each(v1.begin(), v1.end(), myfunction);
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; deque sort(d1.begin(), d1.end()); deque for_each(it, d1.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int multiply (int a) {
return a*2;
}
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector
set
transform(s1.begin(), s1.end(), v1.begin(), multiply);
transform(v1.begin(), v1.end(), s1.begin(), multiply);
for_each(s1.begin(), s1.end(), myfunction);
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int () const { return val;} };
ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< struct Add { B operator()(B & a, B & b) { return a+b; } }; int main() { B t[]={1,2,3,4,5,6,7,8,9,10}; vector v1(t, t+10); vector v2(10); transform(v1.begin(), v1.end(), v2.begin(), bind2nd(Add(),1)); for_each(v2.rbegin(), v2.rend(), Out(cout));cout< return 0; } Program outputs:
What will happen when you attempt to compile and run the following code?
#include
using namespace std;
class C {
public:
int _c;
C():_c(0){}
C(int c) { _c = c;}
C operator+=(C & b) {
C tmp;
tmp._c = _c+b._c;
return tmp;
}
};
template
class A {
T_v;
public:
A() {}
A(T v): _v(v){}
T getV() { return _v; }
void add(T & a) { _v+=a; }
};
int main()
{
A
A
Cc;
a.add(c);
cout << a.getV() < return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
void myfunction(int i) { cout << " " << i;
}
struct sequence {
int val,inc;
sequence(int s, int i):val(s),inc(i){}
int operator()(){
int r = val; val += inc;
return r;
}
};
int main() {
vector
fill(v1.begin(), v1.end(), sequence(1,1));
for_each(v1.begin(), v1.end(), myfunction);
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator()(const T & val ) {
out< } }; struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return start++; } }; struct Odd { bool operator()(int v) { return v%2==0; }}; int main() { vector generate(v1.begin(), v1.end(), Sequence(1)); partition(v1.begin(),v1.end(), Odd()); for_each(v1.begin(), v1.end(), Out return 0; } Choose all possible outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int t[] ={ 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };
list
multiset
if (s1.count(3) == 2) {
s1.erase(3);
}
for(multiset
cout<<*i<<" ";
}
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
int main()
{
deque
stack
stack
stack
stack
fourth.push(10);fourth.push(11);fourth.push(12);
stack
fifth.push(10);fifth.push(11);fifth.push(12);
while(!fifth.empty())
{
cout< fifth.pop(); } while (!fourth.empty()) { cout << fourth.front() << " "; fourth.pop(); } return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
int main ()
{
float f = 10.126;
cout.unsetf(ios::floatfield);
cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main () {
int t[] = {1,2,3,3,5,1,2,4,4,5};
vector
vector
while ( (it = adjacent_find (it, v.end())) != v.end()) {
cout< } cout<< endl; return 0; }
What happens when you attempt to compile and run the following code?
#include
using namespace std;
int main()
{
cout.setf(ios::hex, ios::basefield);
cout<<100.33<<" ";
cout.setf(ios::showbase);
cout<<100.33<<" ";
return 0;
}
Program outputs:
TESTED 04 May 2024
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